
08-06-17, 21:03
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| Όνομα: βασιλης Έκδοση λογισμικού Office: Ms-Office 2007 Γλώσσα λογισμικού Office: Ελληνική | | Εγγραφή: 22-09-2015
Μηνύματα: 72
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καλησπέρα φίλε Σπύρο
το είδα από το τηλ. αυτό που έβαλες άλλα δεν είχα προλάβει να το κοιτάξω στο pc.
σε είπα οτι το listbox και textbox είναι σε userform.
o κώδικας που έχω ειναι αυτος
(Private Sub lstEmployee_DblClick(ByVal Cancel As MSForms.ReturnBoolean)
'dim the variables
Dim i As Integer
On Error Resume Next
'find the selected list item
i = Me.lstEmployee.ListIndex
'add the values to the text boxes
Me.Emp1.Value = Me.lstEmployee.Column(0, i)
Me.Emp2.Value = Me.lstEmployee.Column(1, i)
Me.Emp3.Value = Me.lstEmployee.Column(2, i)
Me.Emp4.Value = Me.lstEmployee.Column(3, i)
Me.Emp5.Value = Me.lstEmployee.Column(4, i)
Me.Emp6.Value = Me.lstEmployee.Column(5, i)
Me.Emp7.Value = Me.lstEmployee.Column(6, i)
Me.Emp8.Value = Me.lstEmployee.Column(7, i)
Me.Emp9.Value = Me.lstEmployee.Column(8, i)
Me.Emp10.Value = Me.lstEmployee.Column(9, i)
Me.Emp11.Value = Me.lstEmployee.Column(10, i)
Me.Emp12.Value = Me.lstEmployee.Column(11, i)
Me.Emp13.Value = Me.lstEmployee.Column(12, i)
Me.Emp14.Value = Me.lstEmployee.Column(13, i)
Me.Emp15.Value = Me.lstEmployee.Column(14, i)
Me.Emp16.Value = Me.lstEmployee.Column(15, i)
Me.Emp17.Value = Me.lstEmployee.Column(16, i)
Me.Emp18.Value = Me.lstEmployee.Column(17, i)
Me.Emp19.Value = Me.lstEmployee.Column(18, i)
Me.Emp20.Value = Me.lstEmployee.Column(19, i)
Me.Emp21.Value = Me.lstEmployee.Column(20, i)
On Error GoTo 0
End Sub)
ευχαριστώ για άλλη μια φορά που ασχολισε .....
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